Question

pls answer the question fast its urgent pls​

Answer 1

Answer:

i) rectangle

ii) both covered same area

iii) given l = 150 b = 50

so we know that,

perimeter of rectangle is 2×(l+b)

= 2×(150+50)

= 2×200

= 400 m

so, the perimeter of satyam's plot is = 400 m

iv) Shivam's plot has more dimensions in

North - South Direction.

v) we know that to find the rate of shivams plot at per square metre we have to find the area of Shivam's plot which is rectangular in shape..

so, we know that area of rectangle is,

= l×b

=150×50

= 7500m2

hope this ans. help you dear....l