Question

pls answer the question mentioned above ​

Answer 1

Answer:

As we can see in the above question that-

ABC is an isosceles triangle.

OBC is an equilateral triangle.

'O' is the centre of the circle.

Angle A is 30°.

ATQ, we need to prove that chord BC is equivalent to the radius of the circle.

As we know that OBC is an equilateral triangle, so that means all of the sides are equal.

Now, if we make a point perpendicular (let's take the point perpendicular to A as X) to A, and then take the line BC and keep it on point X, vertically, then we can see that the line starts from X and ends on O.

I hope this helps you!

Have a great day!