Question

Pls answer the question with proper explanation

Answer 1

Final Answer :5v(1)v(2)/(3v(1) + 2v(2) )

Total distance = x (say)
Time taken when car was moving with speed v1 ,
$t(1) = \frac{ \frac{2x}{5} }{v(1)}$
Time taken when car was moving with speed, v(2)
$t(2) = \frac{ \frac{3x}{5} }{v(2)}$

Now, Average Velocity = Total Distance / Total time
= x/(t(1) +t(2))
= 5v(1)v(2)/(3v(1)+2v(2))

Answer 2

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The answer of u r question is...

is in the pic...

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