Question

pls answer these 2 q's

Answer 1

Answer:

35. There are total 60 students in the class.

36. His fuel will last for a total of 7 days.

Step-by-step explanation:

35. Let us consider there are total x number of students in the class.

Given that,

40% have opted for French, 20% have opted for Sanskrit and remaining 24 students have opted for German.

From question we can say that 40% have opted for German that is nothing but the 24 students.    (40%+20%+y%=100%⇒y%=40%)

This implies that 40% of x=24

⇒$\frac{40}{100}$×x=24

⇒x=24×$\frac{100}{40}$

⇒x=24×$\frac{10}{4}$

⇒x=6×10

∴x=60

36. Given that, Parth had $\frac{4}{5}$ of the fuel tank of which he used 25% on the first day after travelling for 75km.

The amount of fuel remaining after this drive= $\frac{4}{5}$ -25% of  $\frac{4}{5}$

⇒Remaining fuel= $\frac{4}{5}$ -$\frac{25}{100}$× $\frac{4}{5}$

⇒Remaining fuel= $\frac{4}{5}$-$\frac{1}{4}$× $\frac{4}{5}$

⇒Remaining fuel= $\frac{4}{5}$-$\frac{1}{5}$

∴Remaining fuel=$\frac{3}{5}$

After this he would use $\frac{1}{10}$ fuel each day.

Let us say the fuel lasted for y days.

Then we can say that

$\frac{1}{10}$×y=$\frac{3}{5}$

⇒y=$\frac{3}{5}$×10

⇒y=3×2

∴y=6

Hence the total number of days the fuel lasted is y+1 days i.e., for 7 days

(Including day 1).