pls answer these.....
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kartikpatelpatan:
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2)A machinery worth Rs.10500 depreciated by 10%. Find its value after one year.
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1
f) (3a-4b)²
= 9a² + 16b² - 24ab
g) x (3x - 2) - (3x² - 5)
= 3x² - 2x - 3x² + 5
= 5 - 2x
3) a) 4x - 2(x+5) = 3
4x - 2x - 10 = 3
2x = 10 + 3
2x = 13
x = 13/2
b) 3p(p+2) = 0
3p² + 6p = 0
3p + 6 = 0
3p = -6
p = -6/3
p = -2
c) (x+1) (3x - 2) = 0
3x² - 2x + 3x - 2 = 0
3x² + x -2 = 0
d) 2y² + 29y - 15 = 0
2y² + 30y - y - 15 = 0
2y ( y+15) -1 (y+15) = 0
(2y-1) (y+15) = 0
Answered by
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a.4x-2(x+5)=3
4x-2x+10=3
2x+10=3
2x=3-10
2x=-7
x=-7/2
b.3p(p+2)=0
3p square+6p=0
3p square=-6p
p square=-6p/3p
p square=-2p
p=√-2p
c.4x square-2x +3x-2=0
4x square+x=0
4x square=-x
x =√-x/4
I think it's help you
4x-2x+10=3
2x+10=3
2x=3-10
2x=-7
x=-7/2
b.3p(p+2)=0
3p square+6p=0
3p square=-6p
p square=-6p/3p
p square=-2p
p=√-2p
c.4x square-2x +3x-2=0
4x square+x=0
4x square=-x
x =√-x/4
I think it's help you
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