Question

pls answer these questions​

Answer 1

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(a−2d)+(a−d)+a+(a+d)+(a−2d)=55

⟹5a=55

⟹a=11

(a−2d)+(a−d)+5=(a+d)

⟹(11−2d)+(11−d)+5=(11+d)

⟹27−3d=11+d

⟹16−3d=d

⟹16=4d

⟹d=4

a−2d=3

a−d=7

a=11

a+d=15

a+2d=19

Proof:

3+7+11+15+19=55✓

3+7+5=15✓

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Answer 2

Step-by-step explanation:

hope it's helpful for you