Question

pls answer these questions​

Answer 1

$2 {x}^{2} - 4x + 3 = 0$

Since,

$Discriminant = D \\ D= {b}^{2} - 4ac$

So,

$D \: = {( - 4)}^{2} - 4 \times 2 \times 3 \\ = 16 -24 = - 8$

Since,

D > 0

Then the quadratic equation has 2 distinct solutions.

hope it will help u ✨☺️