Pls answer these questions
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que 14. sol...
AFE=CFD (Vertically opposite angle)
AFE=32°
In triangle ABC
A+B+C=180°
A=180-(B+C)
A=180-(47+51)
A=180-98
A=82°
In trialgle AEF
A+E+F=180°
E=180-(A+F)
E=180-(82+32)
E=180-114
E=36°
AEF + BEF = 180 ( Linear Pair)
AEF + a = 180
a = 180 - AEF
a = 180 - 36°
a = 144
AFE=CFD (Vertically opposite angle)
AFE=32°
In triangle ABC
A+B+C=180°
A=180-(B+C)
A=180-(47+51)
A=180-98
A=82°
In trialgle AEF
A+E+F=180°
E=180-(A+F)
E=180-(82+32)
E=180-114
E=36°
AEF + BEF = 180 ( Linear Pair)
AEF + a = 180
a = 180 - AEF
a = 180 - 36°
a = 144
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jaffer58:
Thanksbut answer of Q-14 is 114 on my book
my ans is also 114 check that out
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