Question

Pls answer this !!!

Answer 1

Answer:

Resistance of circuit= R + r

V/I=R+5

10/1=R+5

10=R+5

10-5=R

R=5ohm

so resistance of lamp is 5 ohm.

if 10 ohm resistance is connected in parallel with this series combination then total resistance = 5 ohm

As, potential difference is same in parallel combination

so, current through conductor=10/5=2A

and, potential difference across lamp=10V