pls answer this
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angle BAD will be half of angle bod by theorem that any angle distended from center to any part of circle will be half of the angle distended from the center
there fore BAD=1/2 BOD
BAD=1/2 *140
BAD= 70
now angle bcd will be 90 as per the theorem
angle distended by the center to any part of the arc will be 90 degree
so BAD=70
BCD=90
there fore BAD=1/2 BOD
BAD=1/2 *140
BAD= 70
now angle bcd will be 90 as per the theorem
angle distended by the center to any part of the arc will be 90 degree
so BAD=70
BCD=90
Bansarikikz:
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