Question

Pls answer this .......

Answer 1

there...are....12....ways...they..can.sit.....hope...it's.. right....

Answer 2

9 ARE TO BE ON 1 SIDE.4 ARE ALREADY ON ONE SIDE AND 3 ON OTHER SIDE.

THERE ARE 11 LEFT.  

 

WE CAN SELECT 5 OF THEM IN 11C5 WAYS TO SIT ALONG WITH 4.  

REST WILL AUTOMATICALLY GO TO OTHER SIDE.THIS CAN BE DONE IN ONLY 1 WAY .

NOW 9 ON EITHER SIDE CAN BE ARRANGED IN 9! WAYS...SO THE TOTAL NUMBER OF ARRANGEMENTS ARE  

11C5*9!*9!....