Pls answer this .......
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there...are....12....ways...they..can.sit.....hope...it's.. right....
ankitkumarpal20:
if...my.. ANSWER is usefull.for...u...mark..as...brainliest
what is right... ANSWER?
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9 ARE TO BE ON 1 SIDE.4 ARE ALREADY ON ONE SIDE AND 3 ON OTHER SIDE.
THERE ARE 11 LEFT.
WE CAN SELECT 5 OF THEM IN 11C5 WAYS TO SIT ALONG WITH 4.
REST WILL AUTOMATICALLY GO TO OTHER SIDE.THIS CAN BE DONE IN ONLY 1 WAY .
NOW 9 ON EITHER SIDE CAN BE ARRANGED IN 9! WAYS...SO THE TOTAL NUMBER OF ARRANGEMENTS ARE
11C5*9!*9!....
hope it helps plzz mark as brainliest
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