PLS answer this....
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Answered by
6
Answer:
5/4
Step-by-step explanation:
Given polynomial is f(x) = x² - x - 2
Here, a = 1, b = -1, c = -2
α,β are the zeroes of the polynomial.
(i) Sum of zeroes:
α + β = -b/a
α + β = 1
(ii) Product of zeroes:
αβ = c/a
αβ = -2
Now,
Given: (1/α²) + (1/β²)
⇒ (α² + β²)/α²β²
⇒ [(α + β)² - 2αβ]/[αβ]²
⇒ [(1)² - 2(-2)]/(-2)²
⇒ [1 + 4]/4
⇒ 5/4
Hope it helps!
siddhartharao77:
Thank you :-)
Answered by
0
Solution:
The given Equation is f(x) = x² - x - 2
Here, a = 1 , b = -1 and c = - 2
- a and ß are Zeroes of this Quadratic Polynomial
Relationship Between Zeroes:
☞ Sum of Zeroes = -b/a
a + ß = -b/a
a + b = 1
☞ Product of Zeroes = c/a
aß = c/a
aß = -2
Now, We have to find the value of 1/a² + 1/ß²
☞ 1/a² + 1/ß²
☞ a² + ß² / a².ß²
☞ (a + ß)² - 2ab / (ab)(ab)
☞ (-1)² - 2.-2 / -2 × -2
☞ 1 + 4 / 4
☞ 5/4
Answer is 5/4
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