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A progressive wave moves with a velocity of 36m/sec in a medium with a frequency of 200Hz. The phase difference between two particles separated by a distance of 1cm along the wave is ?
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first finding the wavelength= speed/frequency=> k =36/50now phase difference = (2∏/k )* path difference 60 = (360/36) * 50 * path differencedistance bewtween two nearest points is = path difference = 6/50 metre
madhavsaims2001:
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This is the solution.
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