Question

Pls answer this AP 30th problem

Answer 1

Answer: HOPE THAT IT MAY HELP YOU

Step-by-step explanation:

Sum of n terms of an A.P., S n = n/ 2 [2a + (n – 1)d]

Given that the sum of the first 10 terms is 210.

⇒ 10 / 2 [2a + 9d ] = 210

⇒ 5[ 2a + 9 d ] = 210

⇒2a + 9d = 42 ----------- (1)

15 th term from the last = ( 50 – 15 + 1 ) th = 36 th term from the beginning

⇒ a36 = a + 35d

Sum of the last 15 terms = 15/2 [2a36 + ( 15 – 1)d ] = 2565

⇒ 15 / 2 [ 2(a + 35d) + 14d ] = 2565

⇒ 15 [ a + 35d + 7d ] = 2565

⇒a + 42d = 171 ----------(2)

Multiplying (2)*2

we get d=4 and a=3

a.p=3,7,11,15

Answer 2

Answer:The four numbers are 8, 10, 12, 14.

Hey bro here is your answer if this helps you please mark it as brainliest.

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