Question

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8. A resting stone is dropped from a very high cliff. When it has fallen 5 m, a B stone is dropped.
A. Explain how the distance between the two stones changes as they fall?
B. Determine the speed of stone B when it has traveled 5 m.
C. In a single velocity vs. time graph, sketch the graphs of the two stones when stone B has traveled 10 m. .​

Answer 1

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  A. Separation is increasing at about 9.90 m/s

  B. About 9.90 m/s

  C. See Attached

A. Both stones are accelerated at the same rate, so the difference in their velocities is the velocity stone A had when stone B was dropped.

The distance between the stones increases linearly at that velocity, about 9.90 m/s.

B. The speed when accelerated from rest over some distance d can be found as :-

  v = √(2dg) = √(2(5 m)(9.8 m/s²)) = 7√2 m/s

The speed of stone B at 5 meters is about 7√2 ≈ 9.90 m/s.

C. See the attachment for a velocity vs. time graph. Stone B has traveled 10 m when its velocity is -14 m/s

IMG Source : Microsoft

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