Question

pls answer this asap​

Answer 1

Step-by-step explanation:

this is correct explanation of your answer

Answer 2

SOLUTION:-

$( - 3) {}^{2m + 1} \times ( - 3) {}^{3} = ( - 3) {}^{12}$

We have to find the value of x

Here If you observe In LHS It is in form of

$a {}^{m} \times a {}^{n}$

As we know the exponent laws

$a {}^{m} \times a {}^{n} = a {}^{m + n}$

Since,

$( - 3) {}^{2m + 1} \times ( - 3) {}^{3} = ( - 3) {}^{2m + 1 + 3}$

$= ( - 3) {}^{2m + 4}$

So,

$( - 3) {}^{2m + 1} \times ( - 3) {}^{3} = ( - 3) {}^{2m + 4}$

So,

$( - 3) {}^{2m + 4} = ( - 3) {}^{12}$

As we know that from exponent and laws

If bases are same then powers should be same So,

$2m + 4 = 12$

$2m = 12 - 4$

$2m = 8$

$m = 8 \div 2$

$m = 4$

So, the value of m is 4

Used formulae:-

$a {}^{m} \times a {}^{n} = a {}^{m + n}$

If bases are same then powers should be same

Verification:-

Substitute value of m it shoulf be equal to LHS and RHS

m = 4

$( - 3) {}^{2m + 1} \times ( - 3) {}^{3} = ( - 3) {}^{12}$

$( - 3) {}^{2(4) + 1} \times ( - 3) {}^{3} = ( - 3) {}^{12}$

$( - 3) {}^{8 + 1} \times ( - 3) {}^{3} = ( - 3) {}^{12}$

$( - 3) {}^{9} \times ( - 3) {}^{3} = ( - 3) {}^{12}$

$(-3){}^{9+3} = ( - 3) {}^{12}$

$( - 3) {}^{12} = ( - 3) {}^{12}$

Hence verified!