Math, asked by guruanshpreet7869, 3 months ago

pls answer this b y seeing image

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Answers

Answered by Saby123
2

Solution :

Total Area of the figure :

> Area of Rectangle BCED + Area of triangle ABE

Let us find the length AB first. .

∆ ABE is s right angled triangle.

Applying the Pythagoras theorem ;

AB² = AE² + BE²

AE = 150 cm

BE = 200 cm

AB = √ [ 150 ² + 200² ]

=> AB = 250 cm .

Area of ∆ ABE

> ½ × AE × BE

> ½ × 150 × 200

> 150 × 100

> 15000 cm²

Area of rectangle BCED

> 350 × 200

> 70000 cm²

Total Area :

> 85,000 cm² .

This is the required answer .

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Answered by Anonymous
1

Answer:

Required Answer :-

As we know that

Area of rectangle BCED + Area of Triangle ABE

ABE is a right angled triangle

By Pythagoras Theorem

AB² = AE² + BE²

AB² = 150² + 200²

AB = 22500 + 40000

AB = 250 m

Area of triangle ABE

Area = ½ × AB × BE

Area = ½ × 250 × 200

Area = 1 × 250 × 100

Area = 25000 m²

Area of rectangle BCED

BCED = 350 × 200

BCED = 70,000 m²

Total area = 95,000 m²

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