pls answer this b y seeing image
Answers
Solution :
Total Area of the figure :
> Area of Rectangle BCED + Area of triangle ABE
Let us find the length AB first. .
∆ ABE is s right angled triangle.
Applying the Pythagoras theorem ;
AB² = AE² + BE²
AE = 150 cm
BE = 200 cm
AB = √ [ 150 ² + 200² ]
=> AB = 250 cm .
Area of ∆ ABE
> ½ × AE × BE
> ½ × 150 × 200
> 150 × 100
> 15000 cm²
Area of rectangle BCED
> 350 × 200
> 70000 cm²
Total Area :
> 85,000 cm² .
This is the required answer .
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Answer:
Required Answer :-
As we know that
Area of rectangle BCED + Area of Triangle ABE
ABE is a right angled triangle
By Pythagoras Theorem
AB² = AE² + BE²
AB² = 150² + 200²
AB = 22500 + 40000
AB = 250 m
Area of triangle ∆ABE
Area = ½ × AB × BE
Area = ½ × 250 × 200
Area = 1 × 250 × 100
Area = 25000 m²
Area of rectangle BCED
BCED = 350 × 200
BCED = 70,000 m²
Total area = 95,000 m²