Question

pls answer this.Class 10 maths question​

Answer 1

Answer:

x² + (a+1)x + b

2 and -3 are zeroes of the polynomial,

put x = 2

2² + (a+1)(2) + b = 0

4 + 2a+2 + b = 0

6 + 2a+b = 0

2a+b = -6 -----(1)

put x = -3,

(-3)² + (a+1)(-3) + b = 0

9 - 3a-3 + b = 0

6 - 3a+b = 0

-3a+b = -6 ----(2)

(1) - (2)

2a+b - (-3a+b) = -6-(-6)

2a+b+3a-b = -6+6

5a = 0

a = 0

Explanation: