Question

PLS ANSWER THIS DONT ANSWER IF U DONT KNOW

Answer 1

Answer:

x=4

Step-by-step explanation:

since the term extends indefinitely we can write,

$x = 2 + \sqrt{x}$

The above step is very important and key to solving questions like this. Basically we express the variable in its own terms

Solving,

$x - 2 - \sqrt{x} = 0$

$x - 2 - 2 \sqrt{x} + \sqrt{x} = 0$

$x + \sqrt{x} - 2 - 2 \sqrt{x} = 0$

$\sqrt{x} ( \sqrt{x} + 1) - 2( \sqrt{x} + 1) = 0$

$( \sqrt{x} + 1)( \sqrt{x} - 2) = 0$

Solving we get

x=4 or x=1

But x=1 is neglected because the sum will be more than 2