Question

pls answer this fast​

Answer 1

Tips:

• All Question are based on Mid Point Theorem Class 9.
• Refer Page no. 148 of N.C.E.R.T Maths Book Class 9.

Solution:

Q1.) Option d) ASA

In ∆AED and ∆CEF we have,

AED = CEF [ vert. opp. angle]

AE = CE [ E is the mid point of AC ]

DAE = FCE [ Alt. int. angle ]

So, ∆AED ≈ ∆CEF ( ASA Rule)

Q2.) Option b.) ADE

EFC = ADE [ Alt. Int. Angle ]

Q3.) Option a.) DAE

ECF = DAE [ Alt. Int. Angle ]

Q4.) Option a.) AD

Since ∆AED ≈ ∆CEF ( ASA Rule)

So, AD = CF [ BY C.P.C.T ]

Q5.) Option c.) BD

BD is Parallel to CF

so, BD = CF

Please see the attach for your perfection!