Math, asked by aniket4961, 1 year ago

pls answer this fast

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Answered by vinayakbala32
2

Answer:

sec²A=1/cos²A

cosec²A=1/sin²A

1/cos²A+1/sin²A

=1/cos²Asin²A

=sec²A×cosec²A

HP

PLS MARK IT BRAINLIEST


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vinayakbala32: WHERE IS THAT ANIKET???
mohamedshafeeqpbt7gs: May be offline
vinayakbala32: OH
mohamedshafeeqpbt7gs: Let me also answer
vinayakbala32: BUT THX TO U ANYWAYS
vinayakbala32: ANIKET PLS MARK IT BRAINLIEST
aniket4961: no other person has answered so i cant mark brainliest
vinayakbala32: OH
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