Question

pls answer this fast



9th and 10th ​

Answer 1

SOLUTION 9th:-

Given:

The floor of a room is 8m96cm long & 6m72cm broad.

To find:

The minimum number of square tiles of the same size needed to cover the entire floor.

Explanation:

The floor of a room is 8m 96cm long & 6m 72cm broad.

•We know that, 1m=100cm.

8m= 8×100cm + 96cm

=) (800 +96)cm

=) 896cm

&

6m= 6×100cm + 72cm

=) (600 +72)cm

=) 672cm

Area of the floor:

Length × breadth

=) (896 × 672)cm²

Side of the largest tile that can be used;

HCF of 896 & 672 =224cm.

Therefore,

Area of the tile= side × side

=) 224cm ×224cm

Now,

Number of the tiles required:

$= > \frac{area \: of \: floor}{area \: of \: tile} \\ \\ = > \frac{896 \times 672}{224 \times 224} \\ \\ = > 4 \times 3 \\ \\ = > 12 \: tiles$

&

SOLUTION 10:-

Given:

The number is divisible by 22, 33 & 66.

To find:

A number between 800 & 900.

Explanation:

We take L.C.M of 22,33 & 66.

=) L.C.M. is 66

All multiples of 66 is divisible by 22,33 & 66.

We know that,

=) 66×10=660

=) 66× 11=726

=) 66× 12= 792

=) 66× 13= 858 [This is lies between 800 & 900].

Therefore,

The number is 858 is divisible by 22,33 & 66 and lies between 800 & 900.

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