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POQ is a straight line.OT bisects angle PQR AND OS BISECTS ANGLE QOR.SHOW THAT ANGLE SOT IS A RIGHT ANGLE
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Given - <POQ is a straight line ,
OT bisects <POR , OS bisects <QOR
To proof : <SOT is a right angle
Proof :
POQ is a straight line , & OT bisects <POR ,
so <POT = <TOR --(1)
POQ is a st. line and OS bisects <QOR ,
SO
<ROS = <SOQ --(2)
since
OR stands on POQ
then ,<POR+<ROQ = 180 degree
<POT+<TOR+<ROS+<SOQ= 180 degree <TOR+<TOR+<ROS+<ROS=180 degree
----(from 1&2)
= 2(<TOR+<ROS) = 180 degree
= .<TOR+<ROS = 180/2
= <TOR+,ROS = 90 degree
therefore <SOT = 90 degree
Hence proved.
good morning____________✌️✌️✌️✌️✌️
Given - <POQ is a straight line ,
OT bisects <POR , OS bisects <QOR
To proof : <SOT is a right angle
Proof :
POQ is a straight line , & OT bisects <POR ,
so <POT = <TOR --(1)
POQ is a st. line and OS bisects <QOR ,
SO
<ROS = <SOQ --(2)
since
OR stands on POQ
then ,<POR+<ROQ = 180 degree
<POT+<TOR+<ROS+<SOQ= 180 degree <TOR+<TOR+<ROS+<ROS=180 degree
----(from 1&2)
= 2(<TOR+<ROS) = 180 degree
= .<TOR+<ROS = 180/2
= <TOR+,ROS = 90 degree
therefore <SOT = 90 degree
Hence proved.
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