pls answer this fast as soon as possible
step by step pls need correct answer for
grade 9
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Step-by-step explanation:
Given:-A traingle ABC in which BO and CO are the bisectors of <B and <C respectively
To prove:-<BOC=(90°+1/2<A)
Proof:-
We know that the sum of three angled of a triangle is 180°
<A+<B+<C=180°
1/2<A+1/2<B+1/2<C=90°
1/2<A+<OBC+<OCB=90°
<OBC+<OCB=(90°-1/2<A)
Now,in traingle ABC
<OBC+<OCB+<BOC=180°
(90°-1/2<A)+<BOC=180°
<BOC=180°-(90°-1/2<A)
=(90°+1/2<A)
Hence,<BOC=(90°+1/2<A)
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