Question

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Find the number nearest to 110000 but greater than 100000 which is exactly divisible by each of 8, 15, 21

Answer 1

Answer: 110040

Step-by-step explanation:

Let us first find the LCM of 8,15 and 21.

We get,

8 = 2 x 2 x 2

15 = 3 x 5

21 = 3 x 7

LCM = 2 x 2 x 2 x 3 x 5 x 7

LCM = 840

Now dividing 110000 from 840 we get,

Divisor = 840  Quotient = 130  Remainder = 800

So it should have been 109200

But as 109200 + 840 = 110040 is nearer the answer is 110040.

Hope this was what you wanted.

Answer 2

The number which is divisible by 8, 15, and 21 is also divisible by the L.C.M of the number 8, 15 and 21. The L. C. M of 8, 15, and 21 is 840.

I think u can calculate the LCM.

Thus, the number less than 110000 and nearest to 110000 that is divisible by 840 is 110000 – 800 = 109200

Now, 109200 is also greater than 100000.

Thus, the number nearest to 110000 and greater than 100000 which is exactly divisible by 8, 15, and 21 is 109200.

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