Question

Pls answer this fast... I want appropriate answer plz... ​

Answer 1

Answer:

this is the answer for you question ☝

Answer 2

Step-by-step explanation:

(A+B+C) work in one day = 1/5

(A+C) work in one day = 1/15/2= 2/15

B's work in one day = (A+B+C) work in one day - (A+C) work in one day

= 1/5 - 2/15

=(3-2) / 15

= 1/15

So B can do 1/15 work in one day

so B can complete the work alone in 15 days.

A's work in one day = 1/15

C's work in one day = (A+C) work in one day - A's work in one day

= 2/15 - 1/15

= 1/15

(B+C) work in one day = B's work in a day + C's work in a day

= 1/15 + 1/15

= 2/15

So (B+C) can complete the work in 7 days and 1/2 days

Note:- You can see that efficiency of A, B & C are equal as they all take same days to complete the work alone.

I hope it will help you.