Math, asked by swapnama7, 1 year ago

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The polynomials ky³+3y²-3 and 2y³-5y+k when divided by (y-4)leave the same remainder in each case.find the value of k

Answers

Answered by avnikhurana
2
u first divide y-4 by both the values

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Answered by Anonymous
0

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here is your answer⇒


⇒y-4=0


⇒y=0+4


⇒y=4


⇒ky³+3y²-3


⇒k*(4)³+3*(4)²-3=0


⇒k*64 + 3*16-3=0


⇒64k+48 - 3=0


⇒64k=0+3-48


⇒64k= 3-48


⇒64k=- 45


⇒k=-12845/64


further simply this if u can


2y³-5y+k


2*(4)³- 5*4+k=0


2*64+ -20 +k=0


128+-20+k=0


k= 0+20-128


k= 20-128


k= -108


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hope it helps


pls mark as brainliest



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