PLS ANSWER THIS FAST.............I WILL MARK IT AS BRAINLIEST!!!!
The polynomials ky³+3y²-3 and 2y³-5y+k when divided by (y-4)leave the same remainder in each case.find the value of k
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Answered by
2
u first divide y-4 by both the values
avnikhurana:
u will put there +4
and ur value of k is here
now u mark me as brainliest
plzzz
u have promised me
not any class
its graduation
Answered by
0
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here is your answer⇒
⇒y-4=0
⇒y=0+4
⇒y=4
⇒ky³+3y²-3
⇒k*(4)³+3*(4)²-3=0
⇒k*64 + 3*16-3=0
⇒64k+48 - 3=0
⇒64k=0+3-48
⇒64k= 3-48
⇒64k=- 45
⇒k=-12845/64
further simply this if u can
2y³-5y+k
2*(4)³- 5*4+k=0
2*64+ -20 +k=0
128+-20+k=0
k= 0+20-128
k= 20-128
k= -108
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hope it helps
pls mark as brainliest
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