Question

pls answer this fast pls 7th maths​

Answer 1

Answer:

in 1 fig

x+y+z=180°[angle sum property ]

30°+110°+z=180°

140°+z=180°

z=180°-140°

z=40°

in 2 fig

Step-by-step explanation:

let the third angle connected to the exterior angle be y, then :

80+y=180° (linear pair)

y=180°-80°

y=100°

then,

30+100+x=180° (angle sum property)

130+x=180°

x=180-130

x=50°

hope it will help u....please mark as brainliest

Answer 2

$\bf \huge {\underline {\underline \red{AnSwEr}}}$

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✬First Figure

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In △XYZ

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∠X = 30°

∠Y = 110°

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➞ ∠X + ∠Y + ∠Z = 180° [ Angle Sum Property ]

➞ 30° + 110° + ∠x = 180°

➞ ∠x + 140° = 180°

➞ ∠x = 180° - 140°

➞ ∠x = 40°

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Therefore, value of x is 40°.

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✬Second Figure

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In △ABC

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∠B = 30°

∠QAC = 80°

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➞ ∠QAC + ∠BAC = 180° [ Linear Pair ]

➞ 80° + ∠BAC = 180°

➞ ∠BAC = 180° - 80°

➞ ∠BAC = 100°

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➞ ∠A + ∠B + ∠C = 180° [ Angle Sum Property ]

➞ 100° + 30° + ∠C = 180°

➞ 130° + ∠C = 180°

➞ ∠C = 180° - 130°

➞ ∠C = 50°

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Therefore, value of x is 50°.