Question

pls answer this geometry question soon​

Answer 1

Answer:

✿ Answer:

Given:

∠DBA =2∠CAD

∠ADC=120°

Let ∠CAD=x°

∠DAB=4∠CAD =4x°

2∠DAB = 4X°=2X°

In ∆^le ABD

∠CAB+∠ACB+∠ABC =180

∠ADC=∠DAB +∠DBA

120°=2x° +4x°

6x°=120° ⇒x=20°, ∠CAD =20°

In ∆^le ADC,

∠CAD +ADC+∠ACD=180°

20° +120°+∠ACD=180°

∠ACD=40°

From the diagram

∠AOB=2∠ACD

=2×40°=80°