Math, asked by sathyaprasadm29, 1 month ago

pls answer this I really need to complete it I will mark brainliest .

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Answered by yogini1123
1
  1. AOC+BOC = 180°{linear pair of angles}

(3x-15)+(5x-45)=180°

3x-15+5x-45=180°

8x-60=180°

8x= 180+60

8x= 240°

x = 240/8

x = 30°

2. AOC+COD+BOD= 180°(Linear pair of angles)

55°+x+45°= 180°

100+x= 180°

x = 180-100

x = 80°

3. angle AOC = 50°

BOD = AOC = 50°{vertically opposite angles are equal)

4. AOC+COD+DOB= 180°(Linear pair of angles)

(3x-8)+(50)+(x+10)= 180°

3x-8+50+x+10= 180°

4x-52= 180°

4x = 180+52

4x= 232

x= 232/4

x= 58°

5. AOB+BOC+COD+AOD = 360°( Sum of the angles is 360°)

50°+90°+70°+x = 360°

210+x = 360°

x = 360-210

x = 150°

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