Question

Pls answer this I will mark u as brainliest

Answer 1

A very clear solution is attached nd response to your words dear...

Answer 2

Given that mass of earth is 81.5 times that of moon and moon's diamete is 0.27 times earth's diameter.

$M_e = 81.5 M_m\\ \\ d_m = 0.27m_e\\ \\ \Rightarrow R_m = 0.27 R_e$

$g_e = 9.8\\ \\ g_m = ?\\ \\ g_m \div g_e = \frac{GM_m}{{R_m}^2} \div \frac{GM_e}{{R_e}^2} \\ \\ \frac{g_m}{g_e} = \frac{GM_m}{{R_m}^2} \times \frac{{R_e}^2}{GM_e}$

$\frac{g_m}{9.8} = \frac{M_m}{{(0.27R_e)}^2} \times \frac{{R_e}^2}{81.5M_m} \\ \\ \frac{g_m}{9.8} = \frac{M_m}{{0.0729R_e}^2} \times \frac{{R_e}^2}{81.5M_m} \\ \\ \frac{g_m}{9.8} = \frac{1}{0.0729 \times 81.5} \times \frac{M_m}{{R_e}^2} \times \frac{{R_e}^2}{M_m}$

$g_m = \frac{9.8}{0.0729 \times 81.5} \\ \\ g_m = 1.649 \: \: \frac{m}{ {s}^{2} }$

Hence gravity on moon is 1.649 m/s^2