Question

pls answer this . if someone try to annoy then i will report ​

Answer 1

$\sqrt{2}$Answer:4

Step-by-step explanation: 1 +$\sqrt{2}$ = n

(n - 1/n )²

1 / 1 +$\sqrt{2}$ = 1 / 1 +$\sqrt{2}$  x 1 -√2 / 1 -$\sqrt{2}$

1 -√2/ (1)² - (√2)²

1-√2/ 1 - 2

1-√2/-1

-1 + √2

√2 - 1 = 1 / 1 +$\sqrt{2}$

(1 +√2 -√2 + 1)²

(1 + 1)²

=2²

= 4

(TRUST ME THATS THE ANSWER)

( MARK ME AS BRANIEST PLEASE)

Answer 2

ANSWER = 4

$\huge\sf\underline{\underline{ Given:-}}$

$\large\sf\boxed{x = 1 + √2 }$

$\huge\sf\underline{\underline{To \: Find:-}}$

$\sf value \: of \: (x + \frac{1}{x})^{2}$

$\huge\sf\underline{\underline{Formulas \: Used:-}}$

• $(a+b)² = a² + 2ab + b²$
• $(a - b)² = a² - 2ab + b²$
• $\frac{a}{b} + \frac{c}{d} = \frac{ad+bc}{bd}$
• $(a+b)(a-b) =a² - b²$

$\huge\sf\underline{\underline{ ANSWER:-}}$

$\large\sf\boxed{x = 1 + √2 }$

$\sf (x - \frac{1}{x} ) {}^{2} = {x}^{2} - 2.x. \frac{1}{x} + ( \frac{1}{x} ) {}^{2}$

$\sf\pink{\: \: \: \: \: \: \: \: \: \: \: \: \: \: = {x}^{2} - 2 + \frac{1}{ {x}^{2} } }$

$\rule{15cm}{0.02cm}$

• $\sf (1 + \sqrt{2} ) {}^{2} - 2 + \frac{1}{(1 + \sqrt{2}) {}^{2} }$

$\sf\implies \: \: 1 + 2 \sqrt{2} + 2 - 2 + \frac{1}{(1 + \sqrt{2}) {}^{2} }$

$\sf\implies \: 1 + 2\sqrt{2} + \frac{1}{3 + 2 \sqrt{2} }$

$\sf\implies \: 1 + 2\sqrt{2} + \frac{3 - 2\sqrt{2} }{ {3}^{2} - (2 \sqrt{2}) {}^{2} }$

$\sf\implies \: 1 + 2 \sqrt{2} + \frac{3 - 2 \sqrt{2} }{9 - 8}$

$\sf\implies \: 1 + 3 + 2 \sqrt{2} - 2 \sqrt{2}$

$\sf\pink{\implies \: 4}$

$\rule{15cm}{0.02cm}$