Question

Pls answer this in a little bit detail​

Answer 1

Answer:

4/5

Step-by-step explanation:

The triangles will be similar .

(A1/A2) = √(16/15) = h1/h2 = 4/5

Answer 2

Answer:

The ratio of their corresponding heights is 4 : 5.

Among the given option(d) is correct.

Step-by-step explanation:

Given:

Two isosceles ∆s have equal vertical angles and their areas are in the ratio of 16: 25.

Let the two isosceles triangles be  ΔABC and ΔPQR with ∠A = ∠P.

Therefore,

AB/AC = PQ/PR

In ΔABC and ΔPQR,

∠A = ∠P   (given)

AB/AC = PQ/ PR (sides of a isosceles∆)

ΔABC – ΔPQR    (By SAS similarity)

Let AD and PS be the altitudes(height) of ΔABC and ΔPQR.

We know that the ratio of areas of two similar triangles is equal to the ratio of squares of their corresponding altitudes.

ar(ΔABC)/ar(ΔPQR) = (AD/PS)²

16/25 = (AD/PS)²

√16/25 = √(AD/PS)²

AD/ PS = 4/5

AD : PS = 4 : 5

Hence, the ratio of their corresponding heights is 4 : 5.

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