pls answer this Integration sum
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hope you understand that's very simple question bro
here your another question answer ok which you asked in comment
∫(sec2x/cosec2x)dx
∫(1/cos2x)/(1/sin2x)dx
∫(1/cos2sin) . (sin2x/1)dx
∫tan2x dx
∫(sec2x-1) dx
tanx - x + c
here your another question answer ok which you asked in comment
∫(sec2x/cosec2x)dx
∫(1/cos2x)/(1/sin2x)dx
∫(1/cos2sin) . (sin2x/1)dx
∫tan2x dx
∫(sec2x-1) dx
tanx - x + c
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satyanshsingh468:
no
ok
ok bye
ok here I will ask you my integration sums...help me pls
integrate 1÷1+cosecx
∫
1
1
+
cos
e
c
x
=
∫
1
1
+
1
sin
x
=
∫
sin
x
sin
x
+
1
=
∫
sin
x
(
sin
x
−
1
)
(
sin
x
+
1
)
(
sin
x
−
1
)
=
∫
sin
x
−
sin
2
x
cos
2
x
d
x
=
∫
tan
x
sec
x
d
x
−
∫
tan
2
x
d
x
=
∫
tan
x
sec
x
d
x
−
∫
(
sec
2
x
−
1
)
d
x
=
sec
x
−
(
tan
x
−
x
)
+
c
=
x
+
sec
x
−
tan
x
+
c
1
1
+
cos
e
c
x
=
∫
1
1
+
1
sin
x
=
∫
sin
x
sin
x
+
1
=
∫
sin
x
(
sin
x
−
1
)
(
sin
x
+
1
)
(
sin
x
−
1
)
=
∫
sin
x
−
sin
2
x
cos
2
x
d
x
=
∫
tan
x
sec
x
d
x
−
∫
tan
2
x
d
x
=
∫
tan
x
sec
x
d
x
−
∫
(
sec
2
x
−
1
)
d
x
=
sec
x
−
(
tan
x
−
x
)
+
c
=
x
+
sec
x
−
tan
x
+
c
can u send pic. by doing the sum in copy from next time
in this comment section its difficult to read
ok
pls check my profile for my recent quaries
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