Question

pls answer this it's confusing me​

Answer 1

Answer:

We know that exterior angle is equal to the sum of opposite interior angles.

angle BAC + angle ABC = angle ACD

angle BAC + 50° = 105°

angle BAC = 105-50 = 55°

HOPE IT HELP YOU MY FRIEND

Answer 2

Step-by-step explanation:

First calculate angle ACB

First calculate angle ACB=>angle ACB= 180°–105°=75° [linear pair]

First calculate angle ACB=>angle ACB= 180°–105°=75° [linear pair]Now angle BAC:

First calculate angle ACB=>angle ACB= 180°–105°=75° [linear pair]Now angle BAC:=> angle ACB+ angle BAC+ angle ACB=180° [sum of all angles in a triangle]

First calculate angle ACB=>angle ACB= 180°–105°=75° [linear pair]Now angle BAC:=> angle ACB+ angle BAC+ angle ACB=180° [sum of all angles in a triangle]=>75°+angle BAC+50=180°

=>angle BAC=180°–75°–50°=180°–125°=55°