Question

pls answer this
it's urgently needed
with a solution ​

Answer 1

Answer:

Given: Diagonals AC=30cm and DB=16cm.

Since the diagonals of the rhombus bisect at right angle to each other.

Therefore, OD=

2

DB

=

2

16

=8cm

and OC=

2

AC

=

2

30

=15cm

Now, In right angle triangle DOC,

(DC)

2

=(OD)

2

+(CO)

2

⇒(DC)

2

=(8)

2

+(15)

2

⇒(DC)

2

=64+225=289

⇒DC=

289

=17cm

Perimeter of the rhombus=4× side

=4×17=68cm

Thus, the perimeter of rhombus is 68 cm.

solution