Question

pls answer this nmtc question with steps 11+192+1993+19994+........+1999999999​

Answer 1

11

+ 192 (Keep adding 9 between the digits ofnumbers 12 to 19)

+ 1993

+ 19994

+ 199995

+ 1999996

+ 19999997

+ 199999998

+ 1999999999

=2,22,22,22,175

This is the right answer.

I hope my answer will help u.....

Answer 2

Given :  11+192+1993+19994+199995......1999999999​

To find : Sum

Solution:

11+192+1993+19994+199995......1999999999​

There are total 10 numbers

Unit Digit is from 1 to 9

hence sum = 45  

5 is the unit digit

4 is carried over

tens digits  - 1  + 8 * 9  + 4 ( carried over) =  77

7 is tens digit

7 is carried over

Hundreds digit    1 + 7*9 +  7 (carried over) = 71

1 is hundreds digit

7 is carried over

Next  =  1 + 6*9 + 7  =   62

2 digit

6 carried over

1 + 5*9 +  6  =  52

2 Digit

5 carried over

1 + 4*9 + 5  =  42

2 digit

4  carried over

1 + 3*9 + 4  = 32

2 Digit

3 carried over

1 + 2 * 9  + 3  = 22

2 Digit

2 Carried over

1 + 1 * 9 + 2 = 12

2 Digit

1 Carried over

1 + 1 =  2

2222222175   is the sum

11  + 192  + 1993  + 19994  + 199995  + 1999996  + 19999997  + 199999998  + 1999999999  = 2222222175

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