Math, asked by dhanush1275worldlead, 11 months ago

pls answer this one ​

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Answered by jainishpjain
0

 {cot}^{2} 53 =  {tan}^{2} 37 \\  {tan}^{2} 37 -  {sec}^{2} 37 \\  =  - 1

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Answered by bhavyagoelshanu
1

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