Math, asked by riyas30, 15 hours ago

pls answer this one properly​

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Answered by MrSovereign
5

Required Response:-

Here,

\bf{Σ{f}_{i} = 31+x+y}

\bf{31+x+y = 40}

\bf{x+y = 40-31}

\bf{→\;x+y = 9}

x+y = 9

y = 9-x

\bf{Σ{f}_{i}{u}_{i} = 22-2x-y}

\bf{63.5 = 62.5+\frac{22-2x-y}{\cancel{40}}\times\cancel{5}}

\bf{63.5-62.5 = \frac{22-2x-y}{8}}

\bf{1×8 = 22-2x-y}

\bf{8-22 = -(2x+y)}

\bf{-14 = -(2x+y)}

\bf{→\;2x+y = 14}

By Substituting "y = 9-x" in Equation 2...

\bf{2x+9-x = 14}

\bf{x = 14-9}

\bf{\mapsto\;x = 5}

By Substituting "x = 5" in Equation 1...

\bf{5+y = 9}

\bf{y = 9-5}

\bf{\mapsto\;y = 4}

Value of x is

  • \longmapsto\;\red{\bold{5}}

Value of y is

  • \longmapsto\;\purple{\bold{4}}

Formulas Used:-

\boxed{\sf{Mid\;Point(x_{i}) = \frac{(Upper\; Limit+Lower\; Limit)}{2}}}

\boxed{\sf{Mean = A+\frac{Σ{f}_{i}{u}_{i}}{Σ{f}_{i}}×h}}

\boxed{\tt{@MrSovereign}}

Hope It Helps You ✌️

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