Question

pls answer this
Plssss... Asap​

Answer 1

a) Na₂B₄O₇

(+2) + 4x + 7(-2) = 0

4x = 14 -2

x = +3

b) Fe₃O₄

This is a mixed oxide containing both Ferric oxide(Fe₂O₃)  and Ferrous oxide(FeO)

In Fe₂O₃, oxidation number = +3

In FeO, oxidation number = +2

Average oxidation number = 3+2/2 = +2.5

c) C₆H₁₂O₆

This is Glucose (or fructose) which is an organic molecule, so the oxidation number of Carbon here is 0

d) (NH₄)₂SO₄

2x + (8) -2 = 0

x = -6/2 = -3

e) Na₂S₄O₆

2(+1) + 4x + 6(-2) = 0

x = +2.5

f) NaH₂PO₄

+1 + 2 + x + 4(-2) = 0

x = +5

g) H₄P₂O₇

+4 + 2x + 7(-2) = 0

x = +5

h) Cr₂O₇²⁻

2x + 7(-2) = -2

x = +6

i) KClO₃

+1 +x + 3(-2) = 0

x = +5

j) H₂S₂O₇

+2 + 2x + 7(-2) = 0

x = +6

Hope it helps!