Question

pls answer this ques​

Answer 1

Answer:

75cm is the radius of the circle.

Answer 2

Answer:

BTO will be 90°

(radius is always perpendicular to the tangent at the joining point on circumference

now

since BTO is 90°, ∆ BTO is a right triangle with BO as hypotenuse.

so BO^2 = OT^2 + BT^2

BO = OC+CB = x+10, OT = x, BT = 40

(x+10)^2 = x^2 + 40^2

x^2 + 20x + 100 = x^2 + 1600

20x = 1500

x= 75 cm