Question

pls answer this ques fast...i will mark brainliest and worth 50 points​

Answer 1

First number 4

second number = 7

third number = 10

fourth number 13

fifth number 16

64 = 3 x 21 + 1, which is of the form (3n + 1) for n = 21

343 = 3 x 114 + 1, which is of the form (3n + 1) for n = 114

1000 = 3 x 333 + 1, which is of the form (3n + 1) for n = 333

2197 = 3 x 732 + 1, which is of the form (3n + 1) for n = 732

4096 = 3 x 1365 + 1, which is of the form (3n + 1) for n = 1365

Answer 2

Step-by-step explanation:

Given: 3n + 1.

It was asked for 5 natural numbers. So, plug n = 1,2,3,4,5.

Let n = 1 => 3(1) + 1 = 4

Let n = 2 => 3(2) + 1 = 7

Let n = 3 => 3(3) + 1 = 10

Let n = 4 => 3(4) + 1 = 13

Let n = 5 => 3(5) + 1 = 16

Now,

Cubes of first 5 natural numbers which are in the form of 3n + 1:

(i) 4³ = 64

(ii) 7³ = 343

(iii) 10³ = 1000

(iv) 13³ = 2197

(v) 16³ = 4096.

∴ Cubes of first natural numbers : 64, 343, 1000,2197,4096.

Hope it helps!