pls answer this question
Attachments:
Answers
Answered by
1
YOUR ANSWER
1:4:9
Explained:
we know that,
acceleration=
(final velocity - initial velocity)/time
Therefore,
a=(v-u)/t
v=u+at
Now,
Kinetic energy=m*v*v/2
Substitution of v by the above result,
K.E=[m(u+at)^2]/2
For first second:
K.E=[m(0+a*1)^2]/2
=m(a^2)/2
Similarly,
For 2nd second,
K.E=m(2a)^2/2
For 3rd second,
K.E=m(3a)^2/2
Therefore,
Ratio:
=[m(a^2)/2]:[m(2a)^2/2]:[m(3a)^2/2]
=(a^2):4(a^2):9(a^2)
=1:4:9
Similar questions