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Answered by
1
hi friend,
→AB and CD are parallel
so,y and 75° are interior alternate angles..so they are equal
→y=75°
CD is a straight line
→x+y=180
→x+75=180
→x=105°
→and,75+z and 125 are interior alternate angles..so they are equal.
→75+z=125
→z=50
I hope this will help u ;)
→AB and CD are parallel
so,y and 75° are interior alternate angles..so they are equal
→y=75°
CD is a straight line
→x+y=180
→x+75=180
→x=105°
→and,75+z and 125 are interior alternate angles..so they are equal.
→75+z=125
→z=50
I hope this will help u ;)
Answered by
0
Heya,
Here is the solution:-
In the figure,
75° + x = 180° (∵Sum of angles on the same side of the transversal is supplementary.)
x = 180° - 75°
= 105°
x + y = 180 ( ∵Linear pair)
105° + y = 180°
y = 180° - 105°
= 75°
z + y = 125° (Exterior angle property)
z + 75° = 125°
z = 125° - 75°
z = 50
Hope it helps u.........
Here is the solution:-
In the figure,
75° + x = 180° (∵Sum of angles on the same side of the transversal is supplementary.)
x = 180° - 75°
= 105°
x + y = 180 ( ∵Linear pair)
105° + y = 180°
y = 180° - 105°
= 75°
z + y = 125° (Exterior angle property)
z + 75° = 125°
z = 125° - 75°
z = 50
Hope it helps u.........
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