pls answer this question
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ok i will solve it as you tried but upload a clear pic
arunjoy:
i tried a lot but getting wrong answer
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let v1= 40km/h and v2= 60km/h
As the time for both is unequal
Thus average speed
= 2 v1v2/v1+v2
= 2(40x60)/(40+60)
= 4800/100
= 48km/h
So average speed = 48km/h
As the time for both is unequal
Thus average speed
= 2 v1v2/v1+v2
= 2(40x60)/(40+60)
= 4800/100
= 48km/h
So average speed = 48km/h
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