Question

Pls answer this question​

Answer 1

Answer:

a) 3Ω

b) potential difference across 4Ω = 2v

potential difference across 2Ω = 2v

Explanation:

a) for calculating effective resistance

1. we see that 4Ω and 2Ω resistor are in series
2. and 6Ω and other two resistors are in parallel

So, effective resistance of 4Ω and 2Ω: (in series)

R = R1 + R2

R = 4Ω + 2Ω

R = 6Ω

And now, effective resistance of 6Ω and other two resistance: (in parallel)

$\frac{1}{r} = \frac{1}{r1} + \frac{1}{r2 }$

1/R = 1/6Ω + 1/6Ω

1/R = 2/6

1/R = 1/3

R = 3Ω

Therefore, effective resistance is 3Ω

b) Now, by kirchoffs law when we divide current across 6Ω resistor and (4Ω and 2Ω) resistor we get 1A and 1A current across both resistors respectively.

therefore, when we apply ohm's

V = iR

then potential across 4Ω resistor:

V = 6 - iR

V = 6 - 1×4

V = 2 volt

and potential across 2Ω resistor:

V = 4-iR

V = 4 - 1×2

V = 2 volt

Hope this answers your question and helps you grasp the concept.

Regards:

Aakash Maurya