Question

Pls answer this question​

Answer 1

ANSWER:-

GIVEN:-

AB||CD &CD||EF

.°.AB||EF

<BEF=65°

TO FIND:-

<x, <y, <z.

CALCULATION :-

$\huge\bold\red\rightarrow$CD || EF & EF TRANVERSAL. (GIVEN)

<FED+<EDT=180° ( INTERIOR ANGLE)

65°+y=180° ( <EDT=y)

y=180°-65°

.°.< y=115°

AB||CD & BD TRAVERSAL .

<TDB+<DBS, 180° (INTERIOR ANGLE)

115°+x=180° (<DBS=x)

x=180-115°

.°. <x=65°

HENCE,

<Y=<Z (ALTERNATE ANGLE THEOREM)

<Z=65°

<y=<w (outer alternate angles)

<w=65°