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Answers
Step-by-step explanation:
Inner Radius = Inner Diameter/ 2 = 2 cm
Outer Radius = Outer Diameter / 2 = 2.4 cm
Height of the pipe = 70 cm = h
(i) Inner Surface area of the Pipe
= 2πrh
= 2 * 22/7 * 2 * 70
= 880 cm²
(ii) Outer Surface area of the pipe
= 2πRh
= 2 * 22/7 * 2.4 * 70
= 1056 cm²
(iii) Total Surface Area:
Inner S.A + Outer S.A + 2 * Cross section Surface Area
= 880 + 1056 + 2π(R² - r²)
= 1936 + 2 * 22/7 * (2.4² - 2²)
= 1947.06 cm²
Hope it helps!
inner surface area= 2πrh
=2×22/7×4×70
=44×40
=1760cm^2
inner surface area=1760cm^2
outer surface area= 2πRh
=2×22/7×4.8×70
=44×48
=2112cm^2
outer surface area=2112cm^2
Total surface area= inner surface area+outer surface area+ area of 2bases
inner surface area=1760cm^2
outer surface area=2112cm^2
Area of two bases=2π(R^2-r^2)
=2×22/7(4.8^2-4^2)
=2×22/7{(4.8+4)×(4.8-4)}
=2×22/7×(8.8×0.4)
=2×22/7×3.52
=22.116cm^2
Total surface area= inner surface area+outer surface area+ area of 2bases
TSA=1760+2112+22.116
=3894.116cm^2