Question

Pls answer this question

Answer 1

Answer:

Here is your solution.. Thanks

Answer 2

Answer:

$\implies\dfrac{256}{ {4}^{9x} } = {8}^{2 - x}$

$\implies \dfrac{ {(2)}^{8} }{ {2}^{2(9x)} } = {2}^{3(2 - x)}$

$\implies\dfrac{ {2}^{8} }{ {2}^{18x} } = {2}^{6 - 3x}$

$\implies {2}^{8} = {2}^{18x} \times {2}^{6 - 3x}$

$\implies{2}^{8} = {2}^{18x - 3x + 6}$

$\implies{2}^{8} = {2}^{15x + 6}$

$\because \:The\: bases \:are \:same, \:compare \:the\: power$

$\implies 15x + 6 = 8$

$\implies 15x \ = 8 - 6$

$\implies 15x = 2$

$\implies x = \dfrac{2}{15}$