Math, asked by nairarchana2004, 8 months ago

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Answered by anshikaverma29

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$i^{109}=i^{100}*i^9\\i^{109}=(i^{4})^{25}*(i^3)^3\\i^{109}=(1)^{25}*(i)^3\\i^{109}=1*i\\i^{109}=0+i$

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